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Question

A parallel plate capacitor has rectangular plates of area 400 cm2 and separated by 2 mm with air as a medium. What is the magnitude of charge on each plate if the applied potential difference is 200 Volts?
(Take ϵo=8.85×1012 F/m)

A
3.54×106 C
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B
3.54×108 C
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C
1770.8×109 C
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D
1770.8×1013 C
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Solution

The correct option is B 3.54×108 C
We can solve this problem in two simple steps.


Step 1:

First, let's find the capacitance of the capacitor by using, C=Aϵ0d we get,

C=400×104×8.85×10122×103

C=17.7×1011 F

Step 2: Now Let's use Q=CV

Q=17.7×1011×200=3.54×108 C

Hence, option (b) is correct.

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