A parallel plate capacitor is first charged and then isolated , and a dielectric slab is introduced between the plates. The quantity that remains unchanged is:

charge

Q

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potential

V

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capacity

C

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energy

U

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Solution

The correct option is A charge $Q$
When the capacitor is kept at a voltage, it gains charge.
Now when the system is isolated, the charge present on capacitor cannot change because of law of conservation of charge.
$∴$ Charge always remains constant in isolated systems.

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A parallel plate capacitor is first charged and then isolated , and a dielectric slab is introduced between the plates. The quantity that remains unchanged is:

The correct option is A charge QWhen the capacitor is kept at a voltage, it gains charge.Now when the system is isolated, the charge present on capacitor cannot change because of law of conservation of charge.∴ Charge always remains constant in isolated systems.

The correct option is A charge $Q$
When the capacitor is kept at a voltage, it gains charge.
Now when the system is isolated, the charge present on capacitor cannot change because of law of conservation of charge.
$∴$ Charge always remains constant in isolated systems.