Question

A parallelogram $ABCD$ has sides $AB=24cm,AD=16cm$. The distance between the sides $AB$ and $DC$ is $10cm$. Find the distance between the sides $AD$ and $BC$=

• A. $16cm$
• B. $18cm$
• C. $15cm$
• D. $26cm$

Answer 1

Answer: (C)

$15cm$

$AB=24cm$

$AD=16cm$

$AE=10cm$

area of parallelogram $=AE\times DC=10\times 24$

$=240$

area of parallelogram $=FC\times AD=240$

$FC\times 16=240$

$FC=15cm$