A parallelogram and a triangle are on equal bases and between the same parallel lines. The ratio of their areas is 2:1
1 : 1
Consider the figure given below.
In this figure, ABCD is a parallelogram and ABE is a triangle. Both of them have the same base i.e., AB. The perpendicular EF is an altitude for both triangle and parallelogram.
Now area of ΔABE=12AB×EF
And area of parallelogram is AB×EF.
Hence, Area of parallelogram is twice that of triangle and the ratio will be 2:1