a parcticle has a displacement of 12m towards east and 5m towards north and then 6m vertically upwards. find the magnitude of the sum of these velocities.

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Solution

Let us first calculate the displacement for 12m and 5m.
They act at 90°.So resultant,
R1=sqrt(12^2 +5^2)
= sqrt(169)
=13m
Now calculate for R1 and 6m vertically upward.R1 and 6 will act at 90°.net resultant ,
R2=sqrt(13^2 + 6^2)
=sqrt(205)
=14.32m
so resultant displacement is 14.32m
Note ^ means raised to power

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