Question

A paricle executes SHM with time period of 4 s. find the minimum time interval in which the velocity of the particle changes by an amount equal to its maximum velocity:

• A. $\frac{1}{2}$s
• B. $\frac{2}{3}$s
• C. $\frac{9}{3}$s
• D. $\frac{5}{3}$s

Answer 1

The correct option is A $\frac{1}{2}$s

time period $=4S$

maximum velocity $=W\sqrt{x^2-a^2}$

$=\frac{2\pi }{T}$

$=\frac{2\pi }{4}=\frac{22}{7}\times \frac{1}{2}$