Question

A part of an electric circuit is shown in the figure below :
Using Kirchhoff's $2nd$ law, find the current $I$ flowing through the $4\Omega$ resistor.

Answer 1

From Kirchoff's second law, we have,

given,

$2\times 3+4\times I=2\times 6$

$6+4I=12$

$I=\frac{12-6}{4}$

$\therefore I=\frac{3}{2}A$