Question

A part of circuit is shown in figure. All capacitors have capacitance of $2\mu F$. Find the charge on $C_1$, $C_2$ and $C_3$.

Answer 1

By applying Kirchhoff's law

$C_1(8-V)+C_2(2-V)+C_3(-5)=0$

$2(8-V)+2(2-V)-10=016-2V+4-2V-10=0$

$\Rightarrow V=\frac{10}{4}=2.5Volts$

$q_1=C_1(8-2.5)=2(8-2.5)=11\mu C$

$q_2=12(2-2.5)=1\mu C$

$q_3=2\left(5\right)=10\mu C$