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Question

Four capacitors of capacitance C1=1μF, C2=2μF, C3=3μF and C4=4μF are connected as shown in the figure. Find the potential differences across C3 when switch S is closed.


A
7 V
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B
3 V
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C
7.5 V
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D
2.5 V
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Solution

The correct option is B 3 V

C1 & C2 are in parallel, so the equivalent of these two capacitors is given as

C=C1+C2=(1+2)=3μF

Similarly, C3 & C4 are in parallel, so

C′′=C3+C4=3+4=7μF


Since, C & C" are in series, so the charge on both capacitors in the circuit will be same.

Charge on C= charge on C′′

Let voltage across C and C′′ be V and V′′ respectively.

CV=C′′V′′

V=C′′CV′′=73V′′

Also, given that,

V+V′′=10 V

7V′′3+V′′=10

V′′=3 V

Therefore, potential difference across C3 & C4 will be 3 volts.

So. the right option is (b)

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