A partially dried clay mineral contains 8% water. The original sample contained 12% water and 45% silica. The % of silica in the partially dried sample is nearly:
A
50%
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B
49%
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C
55%
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D
47%
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Solution
The correct option is D 47%
Let us assume the sample as 100 g
Original sample: 12 g of water and 45 g of silica.
Dried sample: 8 g of water and x 12 g of silica.
Total weight of the dried sample becomes =96 g now.
Percentage of silica in dried sample =4596×100=46.87%
Therefore, 47% of silica is present in a partially dried sample.