    Question

# A sample of clay contains 50% silica and 10% water. The sample is partially dried by which it loses 8 g water. If the percentage of silica in the partially dried clay is 52, calculate the percentage of water in the partially dried clay ?

A
4.9%
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B
6.4%
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C
0.58%
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D
0.28%
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Solution

## The correct option is B 6.4%Let weight of clay be x g initially so weight of silica =50100x=0.5x and weight of water =10100x=0.1x After loss of 8 g of water weight of clay will be (x−8) g weight of silica =52100(x−8) g =(0.52x−4.16) g and weight of silica will be same before and after drying so (0.52x−4.16)=0.5x this gives x=208 g So weight of clay after drying =208−8=200 g weight of water initially =0.1 x=0.1×208=20.8 g water loss =8 g final weight of water =20.8−8=12.8 g so, percentage of water in the final clay sample =12.8200×100=6.4%  Suggest Corrections  4      Similar questions  Related Videos   Percentage Composition and Molecular Formula
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