Question

A particle (1) of mass m initially at A is at rest. The radius of circular path is 1 m. The particle (1) , collides at bottom with an other particle (2) of same mass m. The distance travelled by the particle (2) before coming at rest is

• A. 1.5 m
• B. 2.5 m
• C. 3.5 m
• D. 5 m

Answer 1

The correct option is D 5 m

$\begin{array}{c}wall=\Delta K\\ \Rightarrow mg\left(1\right)=\frac{1}{2}m{v}^2\\ \Rightarrow v^2=2g\\ v=\sqrt{2g}\\ Now,\\ v^2=2as\\ \Rightarrow 2g=2\left[\mu g\right]S\\ S=\frac{1}{\mu }=\frac{1}{0.2}=5m\\ Hence,optionDiscorrectanswer.\end{array}$