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Acceleration

A particle A ...

Question

A particle A is moving with a speed of 10 m/s towards right and another particle B is moving at speed of 12 m/s towards left. Find their velocity of approach.

22 m/s

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40 m/s

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15 m/s

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65 m/s

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Solution

The correct option is D 22 m/s
Answer is A.

Velocity of A, B and the difference in the velocities are given as follows.
$v_{A} = + 10 m / s, V_{B} = - 12 m / s \Rightarrow V_{A B} = V_{A} - V_{B} \Rightarrow 10 - (- 12) = 22 m / s$
Since separation is decreasing hence, $V_{a p p} = | V_{A B} | = 22 m / s$ .

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