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Relative Velocity

A particle A ...

Question

A particle A is moving with a speed of 10 m/s towards right, particle B is moving at a speed of 10 m/s towards right and another particle C is moving at speed of 10 m/s towards left. The separation between A and B is 100 m. Find the time interval between C meeting B and C meeting A.

5 s

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3 s

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6 s

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1 s

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Solution

The correct option is A 5 s
Answer is A.
In this case, $t = \frac{s e p a r a t i o n b e t w e e n A a n d C}{V_{a p p} o f A a n d C} = \frac{100}{10 - (- 10)} = 5 s e c$ .
Hence, the time interval between C meeting B and C meeting A is 5 sec.

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