Question

A particle $A$ is moving with a speed of $10\text{m/s}$ towards right and another particle $B$ is moving at speed of $12\text{m/s}$ towards left. Find their velocity of approach.

• A. $-2\text{m/s}$
• B. $10\text{m/s}$
• C. $12\text{m/s}$
• D. $22\text{m/s}$

Answer 1

The correct option is D $22\text{m/s}$

Velocity of particle $A$, $V_A=+10$
Velocity of particle $B$, $V_B=-12$
Velocity of approach, $V_{AB}=V_A-V_B$
$\Rightarrow V_{AB}=10-(-12)=22\text{m/s}$
Velocity of approach = $22\text{m/s}$