Question

A particle can be thrown at a constant speed at different angles. When it is thrown at ${15}^{\circ }$ with horizontal, it falls at a distance of $10m$ from point of projection. For this speed of particle match following two columns.

Answer 1

$\left(A\right)R=\frac{u^2\sin 2\theta }{g}$
$10=\frac{u^2\sin 30}{10}$
$u^2=\frac{100}{\sin 30}=200$
Maximum range is $R_{max}=\frac{u^2}{g}=\frac{200}{10}=20m$
$A\to 2$
$\left(B\right)Maximumheight=\frac{u^2}{2g}=\frac{200}{20}=10m$
$B\to 1$
$\left(C\right)R=\frac{u^2\sin 2\times 75}{g}=\frac{200\times \sin 150}{10}=\frac{200\times \left(1/2\right)}{10}=10m$
$C\to 1$
$\left(D\right)Height=\frac{u^2{\sin }^2\theta }{2g}=\frac{200\times \left(1/4\right)}{20}=\frac{5}{2}m$
Therefore$,D\to 4$