Question

A particle covers 50 m distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed

• A. 100 m
• B. 150 m
• C. 200 m
• D. 250 m

Answer 1

The correct option is C

200 m

$R=\frac{u^{2}sin2\theta }{g}=R\propto u^2$.
o if the speed of projection doubled, the range will becomes four times, i.e., $4\times 50=200m$