Question

A particle executes simple harmonic motion with amplitude $A$. The distance moved by the particle in one oscillation is:

• A. Zero
• B. $A$
• C. $2A$
• D. $4A$

Answer 1

The correct option is D $4A$

Let the distance between the two extreme positions be $d$.

Amplitude is $A$

$⟹d=2A$

Distance travelled by the particle in one oscillation is $2d$ (from one extreme to the second and back from the second extreme to the first).

Hence, total distance $=2d=4A$