A particle executing S.H.M. has an amplitude of $6 c m$ . Its acceleration at a distance of $2 c m$ from the mean position is $8 c m / s^{2}$ . The maximum speed of particle is

8 c m / s

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12 c m / s

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16 c m / s

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24 c m / s

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Solution

The correct option is B $12 c m / s$
$a = - ω^{2} x$
$ω^{2} = 4; ω = 2 \frac{r a d}{s e c}$
$v_{m a x} = ω A = 12 \frac{c m}{s}$

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A particle executing S.H.M. has an amplitude of 6cm. Its acceleration at a distance of 2cm from the mean position is 8cm/s2. The maximum speed of particle is

The correct option is B 12cm/sa=−ω2xω2=4;ω=2radsecvmax=ωA=12cms

A particle executing S.H.M. has an amplitude of $6 c m$ . Its acceleration at a distance of $2 c m$ from the mean position is $8 c m / s^{2}$ . The maximum speed of particle is

The correct option is B $12 c m / s$
$a = - ω^{2} x$
$ω^{2} = 4; ω = 2 \frac{r a d}{s e c}$
$v_{m a x} = ω A = 12 \frac{c m}{s}$