Question

A particle executing SHM has acceleration 12cm/s^2 at 3 cm from its mean position. Time period of particle is

Answer 1

Here acceleration a= 12cm/s^2, displacement x=3cm

Using relation,

a = -ω²x

⇒ 12 = - (2πf )² x

⇒ 12 = - (2π / T )² x

⇒ 12 = (-4 *22 *22 *3) / ( 7*7* T²)

⇒ T² = (-4 *22 *22 *3) / ( 12 *7*7)

⇒ T = -22/7 = -3.14 Sec.

time period is taken positive

So, T = 3.14 sec. Ans