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Question

The velocities of a particle executing SHM are 4cms1 and 3cms1, when its distance from the mean position is 2cm and 3cm respectively. Calculate its time period.

A
5.3s
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B
2.94s
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C
7.31s
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D
9.31s
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Solution

The correct option is C 5.3s
Velocity of particle executing SHM at 2 cm from mean position v1=4 cm/s and at 3 cm from mean position v2=3 cm/s.
v1=ωa2x2=ωa24
v2=ωa2x2=ωa29
v2v1=a29a24=34
16a2144=9a236
a2=1087
Putting the value of a in first equation we get :
ω=1.18s1
Time period, T=2πω=5.3 s

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