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Time Period Independent of Amplitude

A particle ex...

Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :

A

1Hz

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B

3Hz

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C

2Hz

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D

4Hz

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Solution

The correct option is B 1Hz
$V_{m a x} = a ω \Rightarrow f = \frac{ω}{2 π} = \frac{V_{m a x}}{2 π a} = \frac{31.4}{2 π \times 5} = \frac{31.4}{10 π} = 1 H z$

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