A particle experience constant acceleration for $20$ seconds after starting form rest. It travels a distance $S_{1}$ in the first $10$ seconds and distance $S_{2}$ in the next $10$ seconds, then

S_{2} = S_{1}

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S_{2} = 2 S_{1}

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S_{2} = 3 S_{1}

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S_{2} = 4 S_{1}

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Solution

The correct option is C $S_{2} = 3 S_{1}$
$s_{1} = \frac{a}{2} {(10)}^{2} s_{2} = \frac{a}{2} {(20)}^{2} - \frac{a}{2} {(10)}^{2} \Rightarrow \frac{s_{1}}{s_{2}} = \frac{{(10)}^{2}}{30 \times 10} \Rightarrow s_{2} = 3 s_{1}$

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