Question

A particle following S.H.M along $x$ axis, and its $x$ coordinate varies as $x=6+8\sin \omega t.\cos \omega t$. The amplitude of particle is given by

• A. 14
• B. 10
• C. $\sqrt{52}$
• D. 4

Answer 1

The correct option is D 4

$X=6+8\sin \omega t\cos \omega t$
$=6+4\sin 2\omega t$
$A=4$