A particle goes from A to B with a speed of $40$ km/h and B to C with a speed of $60$ km/h. If AB = 6BC, then the average speed in km/h between A and C is (40+x). The value of x is:

Open in App

Solution

Total distance $= A B + B C = 7 B C$

Total time $= \frac{6 B C}{40} + \frac{B C}{60} = \frac{20 B C}{120} = \frac{B C}{6}$

Hence, Average Speed $= \frac{T o t a l D i s t a n c e}{T o t a l T i m e} = 42 k m / h r$

Suggest Corrections

Similar questions

Q. A particle goes from A to B with a speed of 40 km/h and B to C with a speed of 60 km/h. If AB = 6BC, the average speed in km/h between A and C is ____

A car moves with a speed of 40 km/h for the first hour and then with a speed of 60 km/h for the next half hour and finally with a speed of 30 km/h for the next 1.5 hours. What will be the average speed of the car?

Q. With an average speed of 40 Km/h, a train reaches its destination on time. If it goes with an average speed of 35 Km/h, it reaches late by 15 minutes. The total journey is of :

Q. If a person goes from town A to town B by a speed of 50 km/h and comes back with a speed of 150 km/h then average speed of the person is:

Q. A bus goes A to B with 45km /h and return B to A with 85km/h , what is the average speed

Join BYJU'S Learning Program

A particle goes from A to B with a speed of 40 km/h and B to C with a speed of 60 km/h. If AB = 6BC, then the average speed in km/h between A and C is (40+x). The value of x is:

Total distance =AB+BC=7BCTotal time =6BC40+BC60=20BC120=BC6Hence, Average Speed =Total DistanceTotal Time=42 km/hr

A particle goes from A to B with a speed of $40$ km/h and B to C with a speed of $60$ km/h. If AB = 6BC, then the average speed in km/h between A and C is (40+x). The value of x is:

Total distance $= A B + B C = 7 B C$

Total time $= \frac{6 B C}{40} + \frac{B C}{60} = \frac{20 B C}{120} = \frac{B C}{6}$

Hence, Average Speed $= \frac{T o t a l D i s t a n c e}{T o t a l T i m e} = 42 k m / h r$