Question

A particle having initial velocity u moves with a constant acceleration a for a time $t.$ Evaluate it for $u=5m/s,a=2m/s$ and $t=10s.$

Answer 1

The distance travelled is given as,

$s=ut+\frac{1}{2}a{t}^2$

$S=5\times 10+\frac{1}{2}\times 2\times 10$

$s=60m$

The final velocity is given as,

$v=u+at$

$v=5+2\times 10$

$v=25m/s$

Hence distance travelled is $60m$ and final velocity is $25m/s$.