A particle having initial velocity u moves with a constant acceleration a for a time t. What is the position of the particle in the last 1 sec? and how?

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Solution

$d i s \tan c e t r a v e l i n t s e c o n d s, D_{t} = u t + \frac{1}{2} a t^{2} d i s \tan c e t r a v e l i n t i m e (t - 1) . D_{t - 1} = u (t - 1) + \frac{1}{2} a {(t - 1)}^{2} d i s \tan c e t r a v e l i n l a s t s e c o n d i s g i v e n b y : D = D_{t} - D_{t - 1} D = u t + \frac{1}{2} a t^{2} - [u (t - 1) + \frac{1}{2} a {(t - 1)}^{2}] D = u + \frac{a}{2} (2 t - 1)$

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