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Question

A particle having mass 2 kg is moving along a straight line 3x+4y=5 with speed 8 m/s. Find angular momentum of the particle about the origin.

A
20 kg m2s
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B
Zero
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C
16 kg m2s
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D
803 kg m2s
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Solution

The correct option is C 16 kg m2s

As we know,
L=mvr
where r is the perpendicular distance of the line of velocity from the origin.
As we know, perpendicular distance of a line from a point is given as
r=|AX1+BY1+C|A2+B2
Substituting (X,Y)=(0,0)
r=∣ ∣3(0)+4(0)532+42∣ ∣=1
Hence,
L=mvr, where m=2 kg,v=8 m/s,r=1 m
L=2×8×1 kgm2s
L=16 kgm2s

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