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Question

# A particle having mass 2 kg is moving along a straight line 3x+4y=5 with speed 8 m/s. Find angular momentum of the particle about the origin.

A
20 kg m2s
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B
Zero
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C
16 kg m2s
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D
803 kg m2s
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Solution

## The correct option is C 16 kg m2s As we know, L=mvr⊥ where r⊥ is the perpendicular distance of the line of velocity from the origin. As we know, perpendicular distance of a line from a point is given as r⊥=|AX1+BY1+C|√A2+B2 Substituting (X,Y)=(0,0) r⊥=∣∣ ∣∣3(0)+4(0)−5√32+42∣∣ ∣∣=1 Hence, L=mvr⊥, where m=2 kg,v=8 m/s,r⊥=1 m L=2×8×1 kgm2s L=16 kgm2s

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