A particle initially moving with a velocity of 10ms−1 starts decelerating at a constant rate of 5ms−2. The time at which the particle becomes stationary is
A
2 s
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B
0.5 s
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C
1 s
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D
2.5 s
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Solution
The correct option is A2 s Answer (2) u=10ms−1, a=−5ms−2,
v=u+at 0=10−5t ⇒t=2 s