Question

A particle is attached to a vertical spring and is pulled down a distance 4 cm below its equilibrium and is released from rest. The initial upward acceleration is 0.5 ms${}^{-2}$. The angular frequency of oscillation is:

• A. 3.53 rad/s
• B. 0.28 rad/s
• C. 1.25 rad/s
• D. 0.08 rad/s

Answer 1

The correct option is A 3.53 rad/s

$T=2\pi \sqrt{\left|\frac{x}{a}\right|}$
$\therefore$ $\omega =\frac{2\pi }{T}=\sqrt{\left|\frac{a}{x}\right|}$
$=\sqrt{\frac{0.5}{4\times {10}^{-2}}}$
$=3.53$ rad/s