Question

# A particle is fired with velocity u making angle θ with the horizontal. What is the magnitude of change in velocity when it is at the highest point?

A
ucosθ
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B
u
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C
usinθ
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D
(ucosθu)
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Solution

## The correct option is C usinθLet →vi and −→vH be the initial velocity and velocity at highest point respectively. θ is the angle of projection. →vi=ucosθ^i+usinθ^j At the highest point of a projectile, the vertical component of velocity becomes 0 and only horizontal component of velocity exists. −→vH=ucosθ^i Change in velocity can be given as, −→△v=→vf−→vi=−→vH−→vi =−usinθ^j |−→△v|=usinθ

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