CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A particle is fired with velocity u making angle θ with the horizontal. What is the magnitude of change in velocity when it is at the highest point?

A
ucosθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
u
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
usinθ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(ucosθu)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C usinθ
Let vi and vH be the initial velocity and velocity at highest point respectively. θ is the angle of projection.
vi=ucosθ^i+usinθ^j
At the highest point of a projectile, the vertical component of velocity becomes 0 and only horizontal component of velocity exists.
vH=ucosθ^i
Change in velocity can be given as,
v=vfvi=vHvi
=usinθ^j
|v|=usinθ

flag
Suggest Corrections
thumbs-up
16
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving n Dimensional Problems
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon