A particle is moving a long x−axis at time t1=2s, its position is x1=3m and at time t2=7s, its position is x2=18m.The average velocity of the particle is
A
2ms−1
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B
3ms−1
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C
4ms−1
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D
5ms−1
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Solution
The correct option is B3ms−1 The average velocity of the particle is the ratio between the displacement and the time.
vavg=x2−x1t2−t1
or, vavg=18−37−2
or, vavg=3m/s is our required answer. The correct answer is option (B).