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Question

A particle is moving along a circle such that it completes one revolution in 40 seconds.In 2 minutes 20 seconds, the ratio |displacement|distance is

A
0
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B
17π
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C
27π
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D
711π
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Solution

The correct option is C 27π
2 minutes 20 seconds=2×60+20=120+20=140s=40×3+20s

After 2 minutes 20 seconds the particle has completed 3 revolutions and a half revolution,therefore is at the other end of the diameter.

Displacement=2r

Distance covered =3×2πr+πr=7πr

displacementdistance=2r7πr=27π


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