Question

A particle is moving along a circular path of radius $5m$ with a uniform speed $5{ms}^{-1}$. What is the magnitude of average acceleration during the interval in which particle completes half revolution?

Answer 1

After half revolution, the final velocity will be in opposite direction to that of initial velocity.

So, change in velocity $\Delta v=5-(-5)=10m/s$

Time taken $t=\frac{\pi r}{v}=\frac{\pi \times 5}{5}=\pi s$

Average acceleration $a=\frac{\Delta v}{t}=\frac{10}{\pi }m/s^2$