Question

A particle is moving along a circular path, tangential acceleration and angular acceleration are same in magnitude. Then distance covered by the particle in one complete round is

• A. $\frac{\pi }{3}$
• B. $2\pi$
• C. $\frac{\pi }{2}$
• D. $8\pi$

Answer 1

The correct option is B $2\pi$

As we know,
$a=\alpha r$
where, $a$ = tangential acceleration
$\alpha$ = angular acceleration
$r$ = radius

Given that the particle has equal tangential and angular acceleration.
So, $\alpha =\alpha r$
$\Rightarrow r=1m$

In one round, distance covered $=2\pi r=2\pi \left(1\right)=2\pi$