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Question

A particle is moving along a circular path, tangential acceleration and angular acceleration are same in magnitude. Then distance covered by the particle in one complete round is

A
π3
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B
2π
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C
π2
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D
8π
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Solution

The correct option is B 2π
As we know,
a=αr
where, a = tangential acceleration
α = angular acceleration
r = radius

Given that the particle has equal tangential and angular acceleration.
So, α=αr
r=1 m

In one round, distance covered =2πr=2π(1)=2π

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