Question

A particle is moving in a vertical circle. The tension in the string when passing through two platform at angles ${30}^o$ and ${60}^o$ vertical (lowest position) are $T_1$ and $T_2$ respectively

• A. $T_1=T_2$
• B. $T_2>T_1$
• C. $T_1>T_2$
• D. Tension in the string always remain the same

Answer 1

The correct option is C $T_1>T_2$

Tension, $T=\frac{m{v}^2}{r}+mgcos\theta$

For $\theta ={30}^o$

$T_1=\frac{m{v}^2}{r}+mgcos{30}^o$

$=\frac{m{v}^2}{r}+\frac{\sqrt{3}}{2}mg$

For $\theta ={60}^o$

$T_2=\frac{m{v}^2}{r}+mgcos{60}^o$

$\therefore$ $\frac{m{v}^2}{r}+\frac{1}{2}mg$

$T_1>T_2$