Question

A particle is moving on a circular path of radius 5 m with uniform speed 10 $m{s}^{-}1$ from point A to B. The magnitude of average velocity of particle in moving from A to B is

• A. $\frac{2}{\pi }m{s}^{-1}$
• B. $\frac{10}{\pi }m{s}^{-1}$
• C. $\frac{20}{\pi }m{s}^{-1}$
• D. Zero

Answer 1

The correct option is B $\frac{10}{\pi }m{s}^{-1}$

Ref . Image.

i) = change in velocity = 5+5 = 10 m/s.

Time required to distance covered = $\frac{\pi r}{5}=\frac{5\pi }{5}=\pi$

(in semicircle)

Average acceleration = $\frac{changeinvelocity}{time}$

$=\frac{10}{\pi }m/s^2$