Question

A particle is moving on a circular path of radius R with constant speed v. During motion of the particle from A to point B is:

• A. Average speed is v/2
• B. The magnitude of average velocity is $\frac{v}{\pi }$
• C. The magnitude of average acceleration is $\frac{v^2}{\pi R}$
• D. Average velocity is zero.

Answer 1

Answer: (C)

The magnitude of average acceleration is $\frac{v^2}{\pi R}$

From $A$ to $B-$

$|\text{change in velocity}|=2v$

$\text{Time taken}=\frac{2\pi R}{v}$

$|\text{avg. acceleration}|=\frac{\text{|change in velocity|}}{\text{time taken}}=\frac{2v^2}{2\pi R}=\frac{v^2}{\pi R}m/s^2$