A particle is moving towards East velocity $V$ after some time it is moving with velocity $2 V$ towards North. What is magnitude of change in velocity?

V

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\sqrt{3} V

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\sqrt{5} V

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3 V

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Solution

The correct option is C $\sqrt{5} V$
$\begin{matrix} v i = v ˆ i v j = 2 v ˆ j Δ \to V = - \to V j - - \to V i = 2 V \to j - V \to i ∣ ∣ ∣ Δ \to V ∣ ∣ ∣ = \sqrt{4 v^{2} + v^{2}} = \sqrt{5 v} \end{matrix}$
$∴$ Option $C$ is correct.

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A particle is moving towards East velocity V after some time it is moving with velocity 2V towards North. What is magnitude of change in velocity?

The correct option is C √5Vvi=vˆivj=2vˆjΔ→V=−→Vj−−→Vi=2V→j−V→i∣∣∣Δ→V∣∣∣=√4v2+v2=√5v∴ Option C is correct.

A particle is moving towards East velocity $V$ after some time it is moving with velocity $2 V$ towards North. What is magnitude of change in velocity?

The correct option is C $\sqrt{5} V$
$\begin{matrix} v i = v ˆ i v j = 2 v ˆ j Δ \to V = - \to V j - - \to V i = 2 V \to j - V \to i ∣ ∣ ∣ Δ \to V ∣ ∣ ∣ = \sqrt{4 v^{2} + v^{2}} = \sqrt{5 v} \end{matrix}$
$∴$ Option $C$ is correct.