Question

A particle is performing SHM with time period T equals to $\frac{2\pi }{5}s$. The amplitude of the particle is $2cm$. Calculate the maximum velocity of the particle:

• A. $12cm/s$
• B. $8cm/s$
• C. $14cm/s$
• D. $10cm/s$

Answer 1

The correct option is D $10cm/s$

maximum velocity in a SHM $v=A\omega =2\times \frac{2\pi }{T}=2\times \frac{2\pi }{\frac{2\pi }{5}}=10cm/s$