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Question

A particle is projected at an angle 30 with the horizontal at speed 20 m/s. How high will it strike a wall 83 m away from point of projection?
(g=10 m/s2)

A
5 m
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B
4.8 m
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C
2.4 m
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D
9.6 m
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Solution

The correct option is B 4.8 m
x=83, θ=30R=u2sin2θg
=u2×2×sinθ×cosθg
=202×2×12×3210=203
By equation of trajectory of a projectile, we know
y=xtanθ(1xR)y=83×13(183203)=8×(125)=8×35=4.8 m

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