A particle is projected at an angle 30∘ with the horizontal at speed 20m/s. How high will it strike a wall 8√3m away from point of projection? (g=10m/s2)
A
5m
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B
4.8m
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C
2.4m
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D
9.6m
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Solution
The correct option is B4.8m x=8√3,θ=30∘R=u2sin2θg =u2×2×sinθ×cosθg =202×2×12×√3210=20√3
By equation of trajectory of a projectile, we know y=xtanθ(1−xR)⇒y=8√3×1√3(1−8√320√3)=8×(1−25)=8×35=4.8m