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Question

A particle is projected at an angle of 30o to the horizontal and 2 seconds later is moving in the direction tan11/4 to the horizontal for the first time. Find its initial speed. [g=10 m/s2].

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Solution

Equation at time t=0sec

vy=uy

vx=ux

tanθ=uyux

Equation at time t=2sec

vy=uyg(2sec)

vx=ux

tanθ=uyg(2sec)ux

At time t=0sectanθ=13

At time t=2sectanθ=14

Initial velocity will be

=u2x+u2y

Solving for ux and uy we get,

ux=83g43m/s and ux=8g43m/s

And initial velocity will be,

=16g43m/s

=16043m/s


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