A particle is projected from a horizontal plane (x-y plane) such that its velocity vector at time t is given by →V=a^i+(b−ct)^j. Its range on the horizontal plane is given by
A
bac
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B
2abc
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C
3bac
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D
ba2c
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Solution
The correct option is B2abc Given, the velocity of projection as →V=a^i+(b−ct)^j.......(i) Or, →V=Vx^i+Vy^j And we know that Vx=ux and Vy=uy−gt ⇒V=ux^i+(uy−gt)^j......(ii) Comparing (i) & (ii) we have ux=a, uy=b and g=c ∴ Range is given by, R=2uxuyg=2abc