A particle is projected from a horizontal plane (x−z plane) such that its velocity vector at time t is given by →v=a^i+(b−ct)^j. Its range on the horizontal plane is given by
A
bac
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B
2bac
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C
3bac
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D
ba2c
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Solution
The correct option is B2bac According to question vx=ux=a and vy=uy–gt=b–ct On comparing, we get g=c and uy=b We know: R=2(usinθ)(ucosθ)g=2uyuxg ∴R=2bac