Question

A particle is projected from ground as shown in figure. Particle and wedge starts moving simultaneously. If maximum height of inclined so that particle will not hit the inclined is $(g=10m/s^2)$

• A. $\frac{23}{9}$
• B. $\frac{28}{9}$
• C. $\frac{32}{9}$
• D. $\frac{16}{9}$

Answer 1

The correct option is B $\frac{28}{9}$

From the given figure and data we have

$6t=1m+1\times t+l\cos \theta$
$6t=1m+t+l\frac{3}{5}$
$5t=1+\frac{3l}{5}$
$8t-5t^2=4.\frac{l}{5}$
$l=\frac{35}{9}m$
height $=\frac{35}{9}\times \frac{4}{5}=\frac{28}{9}m$