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Standard XII

Physics

Problem Solving

A particle is...

Question

A particle is projected in such a way that it follows a curved path with constant acceleration $\to a$ . for the interval of motion. which of the following option(s) may be correct:
$\to u$ = initial velocity
$\to a$ = acceleration of particles
$\to v$ = instant velocity for t > 0

∣ ∣ \to a \times \to u ∣ ∣ \neq 0

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∣ ∣ \to a \times \to v ∣ ∣ \neq 0

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∣ ∣ \to u \times \to v ∣ ∣ \neq 0

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All of these

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Solution

The correct option is D All of these
$\to a$ is constant
motion is along curve path so initially angle $θ$ between $\to u$ and $\to a$ $\neq 0$
$(A)$ $∣ \to a \times \to u ∣\neq 0$ is correct
$(B) & (C)$ direction of $\to v$ is between $\to a$ and $\to u$ so $∣ \to a \times \to v ∣\neq 0$ and $∣ \to V \times \to U ∣\neq 0$ is correct

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A particle is projected in such a way that it follows a curved path with constant acceleration →a. for the interval of motion. which of the following option(s) may be correct:→u = initial velocity→a = acceleration of particles→v = instant velocity for t > 0

The correct option is D All of these→a is constantmotion is along curve path so initially angle θ between →u and →a ≠0(A) ∣→a×→u∣≠0 is correct(B)&(C) direction of →v is between →a and →u so ∣→a×→v∣≠0 and ∣→V×→U∣≠0 is correct

A particle is projected in such a way that it follows a curved path with constant acceleration $\to a$ . for the interval of motion. which of the following option(s) may be correct:
$\to u$ = initial velocity
$\to a$ = acceleration of particles
$\to v$ = instant velocity for t > 0