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Relative Velocity in 2D

A particle is...

Question

A particle is projected up with an initial velocity of $80$ the ball will be at a height of $96$ from the ground after

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Solution

Initial Velovity = U₀ = 80feet/second.

Height = H = 80 feet.

Acceleration due to gravity = g = 32 feet/s².

Using kinematic 2^nd equation.

H = U₀t + at²/2.

96 = 80t -32t²/2.

t²-5t +6 =0.

Solving above equation We get

t = 2seconds and 3 seconds.

It means when particle goes to upward direction then at 2seconds it is at 96 feet height.

and at the returing time at 3seconds its height is 96feet.

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