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Standard X

Physics

Potential Energy of an Object at a Height

A particle is...

Question

A particle is projected vertically upwards from a point $A$ on the ground. It takes $t_{2}$ seconds to reach a point $B$ at a height $^{'} h^{'}$ from $A$ but still continue to move up. If it takes further $t_{2}$ seconds from $B$ to the ground again, then find maximum height reached.

\frac{g}{2} t 1 t 2

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\frac{g (t_{1} + t_{2})^{2}}{4}

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\frac{g (t_{1} + t_{2})^{2}}{6}

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\frac{g (t_{1} + t_{2})^{2}}{8}

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Solution

The correct option is A $\frac{g}{2} t 1 t 2$
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A particle is projected vertically upwards from a point A on the ground. It takes t2 seconds to reach a point B at a height ′h′ from A but still continue to move up. If it takes further t2 seconds from B to the ground again, then find maximum height reached.

The correct option is A g2t1t2undefined

A particle is projected vertically upwards from a point $A$ on the ground. It takes $t_{2}$ seconds to reach a point $B$ at a height $^{'} h^{'}$ from $A$ but still continue to move up. If it takes further $t_{2}$ seconds from $B$ to the ground again, then find maximum height reached.

The correct option is A $\frac{g}{2} t 1 t 2$
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